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(3x^2)-243x^-2=0
We add all the numbers together, and all the variables
3x^2-243x-2=0
a = 3; b = -243; c = -2;
Δ = b2-4ac
Δ = -2432-4·3·(-2)
Δ = 59073
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-243)-\sqrt{59073}}{2*3}=\frac{243-\sqrt{59073}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-243)+\sqrt{59073}}{2*3}=\frac{243+\sqrt{59073}}{6} $
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